The sum f two number is 184 if one third of the one exceed on seventh of other by 8. find the number
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let the no. be x
ATQ,
x/3+8 = 184-x/7
x+24/3 = 184-x/7
7x+168 = 552-3x
7x+3x = 552-168
10x = 384
x = 384/10
x = 192/5
therefore, the no. is 192/5
ATQ,
x/3+8 = 184-x/7
x+24/3 = 184-x/7
7x+168 = 552-3x
7x+3x = 552-168
10x = 384
x = 384/10
x = 192/5
therefore, the no. is 192/5
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