Question

a rectanglular park is 66m long and 44 m board two crossing paths at right angle each of 3m wide are running across the middle of the park calculate i)the cost of paving the bricks of size 20cm by 15cm on the paths at rs 15000 per 1000 bricks ii)the cost of covering the empty space with turfs at rs20 per sq meter

Answer 1

Answer:

Step-by-step explanation:

total area of the park = 66m * 44m = 2904m^2

area of path (horizontal) = 3*66 = 198m^2

area of path(vertical) = 3*44 = 132m^2

area of intersection = 9m^2

total = 198m^2 + 132m^2 - 9m^2 = 321m^6

remaining area = 2904m^2 - 321m^2 = 2583m^3

(i) area of 1 brick = 20cm * 15cm = 300cm^2 = 0.03m^2

no. of bricks = 321/0.03 = 10700

cost of 1000 bricks = 15000

cost of 1 brick = 15

cost of 10700 bricks = 15*10700 = 160500

(ii) area of remaining park = 2583m^2

cost per m sq = 20

total cost = 51660