Question

a rectangular aheet of paper is 12whole1/2cm long and 10 whole2/3cm wide.Find its perimeter and area

Answer 1

perimeter = 2(l+b)
so
$2(12 \frac{1}{2} + 10 \frac{2}{3}) \\ = 2( \frac{25}{2} + \frac{32}{3} ) \\ 2( \frac{75 + 64}{6} \\ 2 \times \frac{139}{6} = \frac{139}{3}$
area = l*b
so
$\frac{25}{2} \times \frac{32}{3} \\ = \frac{400}{3}$
hope it helps mark it brainliest
400/3 = 133.34

Answer 2

Hii friend,

Length of rectangle= 12 1/2 = 25/2 = 12.5 cm

Breadth of rectangle = 10 2/3 = 32/3 = 10.66 cm

Therefore,

Area of rectangle = Length × Breadth = 12.5 × 10.66 = 133.25 cm².

And,

Perimeter of rectangle = 2(L+B) = 2(12.5+10.66) = 2 × 23.16 = 46.32 cm. = 4632/100 = 1158/25 = 46.32 cm

HOPE IT WILL HELP YOU..... :-)