A rectangular assembly hall has a ratio of its length to its width to be 2:3. The perimeter of the hall is 30 units.
What is its area?
Answers
Step-by-step explanation:
2:3
let x be the multiple
2x and 3x
2x * 3x = 30
6x=30
x= 30÷6
x= 5
2x=10
3x=15
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Solution!!
The ratio of the length to breadth of a rectangular assembly hall is given in the question along with the perimeter of the hall. We have to find the area of the rectangular hall.
Ratio = 2:3
Perimeter = 30 units
Now, let the ratio be 2x and 3x.
Length = 2x
Breadth = 3x
We will use the perimeter formula to find the value of x.
Perimeter = 2(Length + Breadth)
30 = 2(2x + 3x)
30 ÷ 2 = 2x + 3x
15 = 5x
x = 3
2x = 2 × 3 = 6
3x = 3 × 3 = 9
Hence,
Length = 6 units
Breadth = 9 units
Now that we know the length and breadth, we can easily find the area of the hall.
Area = Length × Breadth
Area = 6 units × 9 units
Area = 54 sq. units
Hence, the area of the hall is 54 sq. units!!