Question

A rectangular block of dimensions 8m x 6m x 2m and of density 3gm/c. c is lying on horizontal ground with the face of largest area in contact with the ground. The work done in arranging it with its smallest area in contact with the ground is, (g = 10ms=2) send this answer​

Answer 1

Answer:

$\sqrt[. |?| ]{?}$

Answer 2

Answer:

m= v×density

m=8×6×2×3×10^3= 288×10^3 kg

when face with large area is in contact with the ground its height is 2m

Centre of mass is at a height of 1m

when face with small area is in contact with the ground its height is 6m

Centre of mass is at a height of 3m

W=288×10^3(3-1)= 5760kJ