Question

a rectangular block of glass is placed
on a mark made on the surface of
table and is viewed from the vertical
Position of the eye if the refractive index of
glass be ų and its thickness d, of the the
mark will appear
to be raised up by :​

Answer 1

Answer:

x=d(μ−1)/μ

Explanation:

By definition μ=actual depth/Apparent depth

Let the mark be raised by a distance x.

So, μ=d/(d−x)

On solving we get, x=d(μ−1)/μ