Question

A rectangular block of ice measures 50 cm by 20 cm by 15 cm. If ice weighs
$\frac{9}{10}$
of the same
volume of water and 1 cubic centimetre of water weighs 1 gm, calculate its mass in kg.


please provide a step by step explanation​

Answer 1

Question:-

A rectangular block of ice measures 50 cm by 20 cm by 15 cm. If ice weights 9/10 of the same volume of water and 1 cubic centimetre of water weighs 1 gm, calculate its mass in kg.

Required Answer:-

Given:-

• The dimension of rectangular ice block is 50cm by 20cm by 15cm
• The ice weights 9/10 of the same volume of water.
• 1 cm³ water weights 1g

To Find:-

• Calculate the mass of ice block in kg.

Solution:-

We know that:-

Volume of a rectangular block = lbh

Where,

• l is length
• b is breadth
• h is height

Therefore,

Volume of the ice block = 50cm × 20cm × 15cm

=> Volume of the ice block = (50 × 20 × 15)cm³

=> Volume of the ice block = 15000cm³

Now, we were given:-

The ice weights 9/10 of the same volume of water.

Which means if the water weights x units, the ice will weight (9/10 × x)units.

Hence,

1cm³ water weights 1g

∴ 1cm³ ice block weights (9/10 × 1)g = 0.9g

Now,

1cm³ ice block weights 0.9g

∴ 15000cm³ ice block weights (0.9 × 15000)g = 13500g

As we know that :- 1000g = 1kg

∴ 15000cm³ ice block weights = (13500/1000)kg = 13.5kg

Hence,the mass of the ice block is 13.5kg