Question

A rectangular block of metal of density 8000 kg/m3 measures 2cm by 3 cm by 10 cm. What is the mass of the block?

Answer 1

Explanation:

$density = \frac{mass}{volume}$

$volume = 2 \times 3 \times 10 = 60 {cm}^{3}$

$1 \: m = 100 \: cm \\ 1 \: {m}^{3} = 1000000 \: {cm}^{3} \\ \frac{60}{1000000} = 0.00006 \: {m}^{3}$

$mass = 8000 \times 0.00006 \\ mass = 0.48 \: kg$