A rectangular box has dimensions 68 cm × 80 cm × 50 cm. We need to carry small cubes of edge size 5cm in the box. How many can we carry in the box?
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Answered by
3
volume rectangular box=68*80*50=272000cm^3
volume of a cube of 5cm edge=5^3=125cm^3
now cubes can be carried in the rectangular box=(272000/125)=2176 cubes
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but in the side 3cm space remains unoccupied
therefore volume used=65*50*80=260000cm^3
then total no of cubes can be put into the box= 260000/125 =2080
volume of a cube of 5cm edge=5^3=125cm^3
now cubes can be carried in the rectangular box=(272000/125)=2176 cubes
plz mark it as brainliest
but in the side 3cm space remains unoccupied
therefore volume used=65*50*80=260000cm^3
then total no of cubes can be put into the box= 260000/125 =2080
BrainlyGood:
no. Incorrect answer
(65*50*80)/125 =260000/125 =2080 this is the right answer
in this all sides are the multiple of 5
right. .2080
Answered by
3
Answer:
volume rectangular box is equal to 68 8050 ok
volume volume of cube of 5 cm is equal to 125 CM
now cubes can be carried in a rectangular box (27 2000/125=2176) cubes
but in the side 3 cm it
cannot occupy space
therefore volume used is equal to 65,50, 80
2600000 CM
then then the total number of cubes in the box is equal to 26 lacs by 125 is equal to 2080
hope it's helpful for you ok
this is the correct information of your question
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