Question

a rectangular box is 17.5 cm long, 13cm wide and 10cm high . find its total surface area​

Answer 1

Answer:

TSA = 2(lb+bh+hl)

TSA = 2 ( 17.5*13+13*10+10*17.5 )

TSA = 2 ( 227.5 + 130 + 175 )

TSA = 2 * 532.5

TSA = 1065 cm ^2

Therefore , its total surface area is 1065 cm ^ 2

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Answer 2

Given:

Length of the cuboidal box = 17.5 cm

Breadth of the cuboidal box = 13 cm

Height of the cuboidal box = 10 cm

To Find:

The total surface area of the box.

Solution:

In this question, we are given the length, breadth and height of the box and is asked to find the total surface area of the box. The formula to be used here:

$\sf{\implies\:TSA\:of\:a\:cuboid=2(lh+bh+lb)}$

Applying the same formula here:

$\sf{\longrightarrow\:TSA=2[(17.5\times10)+(13\times10)+(17.5\times13)]}$

$\sf{\longrightarrow\:TSA=2(175+130+227.5)}$

$\sf{\longrightarrow\:TSA=2\times532.5}$

$\sf{\longrightarrow\:TSA=1065\:cm^2}$

The TSA of the cuboid is 1065 cm².

Total Surface Area:

The total surface area of any figure refers to the area of the material used to build the figure. This is just a two-dimensional value to denote the total area of the material.

➡ Some important formulae related to a cuboid:

✳ LSA = 2 (lh + bh)

✳ TSA = 2 (lh + bh + lb)

✳ Volume = lbh