Physics, asked by rithwick8667, 1 year ago

A rectangular coil of 300 turns has an average area of average area of 25 cm × 10 cm. The coil rotates with a speed of 50 cps in a uniform magnetic field of strength 4 × 10⁻² T about an axis perpendicular of the field. The peak value of the induced e.m.f. is (in volt)
(a) 3000π
(b) 300π
(c) 30π
(d) 3π

Answers

Answered by saiyedansari65
0
The peak value of the included 3π....
Answered by Anonymous
16

Answer: (c) 30π

Explanation:

Given data

Number of turns of coil = 300 = n

area = 25 cm × 10 cm. =A

speed of coil = 50 cps =w

magnetic field strength 4 × 10^-2 T = B

B is about an axis perpendicular of the field

Therefore θ= 90°

sin90=1

To find: The peak value of the induced e.m.f.

We know that

E = nBA ω sin θ

= (300)*(4*10^-2)*(25*10^-2) *(10*10^-2)*2π*50 *1

= 30πvolts

Hence peak value of induced emf = 30π volts

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