The average e.m.f. induced in a coil in which the current changes from 2 ampere to 4 ampere in 0.05 second is 8 volt. What is the self inductance of the coil ?(a) 0.1 H(b) 0.2 H(c) 0.4 H(d) 0.8 H
Answers
Answered by
23
Correct Answer : OPTION B: 0.2H
Explanation:
e= 8 volts
i= 4- 2 A
T=0.05 S
e= −Ldi/dt
8=L(4−2)/0.05
L=0.2 H
Answered by
7
Answer:
b) 0.2H
Explanation:
Change in current = 2 to 4 amperes (Given)
Time taken = 0.05 seconds (Given)
EMF = e = 8 volts (Given)
Time = i = 4- 2 A ( due to the change)
According to the Faraday's law, the Induced EMF is equal to the rate of change of the magnetic flux.
Magnetic flux = Magnetic field strength x Area = BA.
Therefore, the induces EMF = (change in Magnetic Flux Density x Area)/change in Time.
EMF = (change in flux)/ time
e = −Ldi/dt
8 = L(4−2)/0.05
0.4 = L(2)
L = 0.2 H
Thus, the self inductance of the coil is 0.2H.
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