The mutual inductance between two coils is 1.25 henry. If the current in the primary changes at the rate of 80 ampere/second, then the induced e.m.f. in the secondary is(a) 12.5 V(b) 64.0 V(c) 0.016 V(d) 100.0 V
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16
Correct Answer : option d: 100.0 V
Explanation :
Current changes =di/dt= 80 A/seconds
Mutual Inductance = 1.25henry
e=M di/dt
=1.25x 80
=125x80/100
=100 V
Answered by
13
Given,
Current = 80Amp/Sec
Mutual Inductance = 1.25Hz
e = M di/dt
1.25×80
125×80×100
100V.
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