A rectangular coil of wire of 50 turns and dimensions 6cm×9cm carries a current of 10mA. If a magnetic field of magnitude 0.5T is applied parallel to the plane of the coil. What is the magnitude of the torque acting on the coil? Also find the magnitude of the torque when the magnetic field makes an angle of 30degree and 0degree with the normal to the plane of the coil.
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Explanation:
The torque on a loop in uniform magnetic field is given by
τ=
M
×
B
τ=MBsinθ [where θ is angle between normal and the plane of loop]
As the coil is inclined at an angle of 30
o
with magnetic field so area vector will be inclined at an angle of 60
o
with the field.
M=NI×πr
2
=50×2×.12×.1=1.2
B=.2T
τ=1.2×.2×sin60
∘
τ=0.2Nm
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