A rectangular courtyard is 18m 72 cm long 13 m 20 m broad .it is to paved with square tiles of the same size .find the least possible no of such tiles
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Answered by
70
Heya !!!!!
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length of courtyard = 18m 72cm = 1872cm
breadth of courtyard = 13m 20cm = 1320 cm
take HCF of 1872 and 1320
1872 = 1320 * 1 + 552
1320 = 552 * 2 + 216
552 = 216 * 2 + 120
216 = 120 * 1 + 96
120 = 96 *1 +24
96 = 24 * 4 + 0
HCF of 1872 and 1320 = 24
no of tiles = area of courtyard / area of side of tile
= 1872 * 1320 /24 *24
= 4290
4290 tiles of same size can paved in the rectangular courtyard.
_________________
Hope u like it :))
# Nikky
all the best :))
____________________
length of courtyard = 18m 72cm = 1872cm
breadth of courtyard = 13m 20cm = 1320 cm
take HCF of 1872 and 1320
1872 = 1320 * 1 + 552
1320 = 552 * 2 + 216
552 = 216 * 2 + 120
216 = 120 * 1 + 96
120 = 96 *1 +24
96 = 24 * 4 + 0
HCF of 1872 and 1320 = 24
no of tiles = area of courtyard / area of side of tile
= 1872 * 1320 /24 *24
= 4290
4290 tiles of same size can paved in the rectangular courtyard.
_________________
Hope u like it :))
# Nikky
all the best :))
Answered by
35
Hey friend check the answer below
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Length = 1872 cm
Width = 1320 cm
The edge of the square tile must be the common divisor of the dimensions of the courtyard.
So, maximum edge of square tile = HCF of 1872 and 1320 = 24 cm
So, required number of tiles = area of courtyard/ Area of square tile = 1872 x 1320/ (24)2 = 4290
Thus, the least number of tiles required to cover the courtyard is 4290.
Hope you got the answer
And you should mark brainliest
________________________________________________
Length = 1872 cm
Width = 1320 cm
The edge of the square tile must be the common divisor of the dimensions of the courtyard.
So, maximum edge of square tile = HCF of 1872 and 1320 = 24 cm
So, required number of tiles = area of courtyard/ Area of square tile = 1872 x 1320/ (24)2 = 4290
Thus, the least number of tiles required to cover the courtyard is 4290.
Hope you got the answer
And you should mark brainliest
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