Question

A rectangular cube of edge 16cm is immersed completely in a rectangular vessel containing water. if the dimensions of the base of vessel are 25cm x 16cm, find the rise in water level.

Answer 1

Increase in volume=Volume of cube=(16×16×16)cm3

Rise in water level=volume/area=16×16×16/25×16=4096/400=10.24cm

I hope it will help you....

Answer 2

Answer:

10.24 cm

Step-by-step explanation:

Length of edge of cube = 16 cm

Volume of cube = $Side^3 = 16^3 =4096 cm^3$

Length of vessel = 25 cm

Breadth of vessel = 16 cm

Area of vessel = $Length \times Breadth = 25 \times 16 = 400 cm^2$

Now the rise in water level = Volume of cube immersed / Area of vessel

So, Rise = $\frac{4096}{400}$

Rise = $10.24 cm$

Hence The rise in water level is 10.24 cm