a rectangular field 70m by 50m has two path running in the middle of it one parallel to length and other to breath the width of a longer and shorter Parts are 3 m and 5m respectively find the area of path and the area of remaining parts of the field
Answers
Answer:1.a rectangular field 70m long and 50m wide has a path of uniform width around it . if the area of the path is 1024 sq.m.find the width of the path
---
Draw the picture of a rectangle inside a rectangle.
---
The area of the inner rectangle is 70*50 = 3500 sq. meters
---
Area of the outer rectangle = (70+2x)(50+2x) = 4X^2 + 240x + 3500
----
Equation:
Outer area - Inner area = 4x^2+ 240x = 1024
x^2+60x-256 = 0
(x-4)(x+64) = 0
---
Positive Solution:
x = 4 meters.
====================
2.The base and height of a triangle are (x+3) and (2x-5)cm respectively if the area of the triangle is 20 sq.cm find x
------------------
Area = (1/2)(base)(height)
20 cm^2 = (1/2)(x+3)(2x-5)
40 = 2x^2+x-15
---
2x^2+x-55 = 0
(x-5)(2x+11) = 0
Positive solution:
x = 5
-----
base = x+3 = 9 cm
height = 2x-5 = 5 cm
=====================
3.The length of a rectangle is 5cm longer than its width and its area is 66 sq.cm find the perimeter of the rectangle.
---
Let width = x
The length = x+5
---
Equation:
x(x+5) = 66
x^2+5x-66 = 0
(x+11)(x-6) = 0
---
Positive Solution:
x = 6 cm
---
Perimeter = 2(width + length)
P = 2(6 + 11)
P = 2(17)
Perimeter = 34 cm
======================
Cheers,
Stan H.
==============
Step-by-step explanation:
Answer:
hope it helps
Mark me as BRAINLIEST
