Question

A rectangular field 70mby 50m has two paths running in the middle of it, one parallel to length and other to breadth.the width of a longer and shorter parts are 3m and 5m respectively.find the area of path and the area of remaining parts of the field.

Answer 1

Answer:

Step-by-step explanation:

Area of the rectangle = Length×Breadth=65×50=3250m2

Given Width of the Path = 2m

Length of the Path is Parellel to the side , Hence Length = 65 m

Area of the Path 1 = Length×Width=65×2=130m2

Given Breadth of the Path = 2m

Length of the Path2 is Parellel to the other side , Hence Length = 50 m

Area of the Path2 = Length×Breadth=50×2=100m2

Add Both the Area of the Path = 130+100=230m2

Area of the Common Field ABCD = 2×2=4m2

As both path are overlapping each other, so to calculate the area of shaded portion area of one square should be deducted from the area of the total path.

∴ Total Area for the Path Construction = 230−4=226m2

∴ Cost of Constructing the Path = 230−4=226×69=15594