If one root of the equation x^2-8x+m=0 is 2, then the other roots will be
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The root is 2
p (x)=x^2-8x+m=0
p (2)=4-16+m=0
=-12+m=0
=m=12
p (x)=x^2-8x+m=0
p (2)=4-16+m=0
=-12+m=0
=m=12
Answered by
0
Answer:
The equation's solutions are 2 and 6.
Step-by-step explanation:
x2 - 8x Plus m = 0 is the quadratic solution that is provided. It is well known that this equation's first root is 2. The other equational root must be located.
Let's use the information that the product of the roots is given by c/a and the total of the roots is given by -b/a for the quadratic equation ax2 + bx + c = 0.
We know that one root of the equation x2 - 8x + m = 0 is 2. Call the second root r. The total of the bases is then:
Using the sum of roots method, 2 + r = -(-8)/1 = 8.
When we solve for r, we get:
r = 8 - 2\s= 6
As a result, the provided equation's solutions are 2 and 6.
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