Math, asked by rishimenon8073, 1 year ago

If p and q are the zeroes of the polynomial 2x^2+5x+k, find the value of k such that (p+q)^2-pq=24 accordingtoclass10th

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Answered by BEJOICE
0

from \:  \: the \:  \: polynomial \\ p + q =  \frac{ - 5}{2} . \:  \:  \: pq =  \frac{k}{2}  \\  {(p + q)}^{2}  - pq = 24 \\  {( \frac{ - 5}{2}) }^{2}  -  \frac{k}{2}  = 24 \\ 25 - 2k = 96 \\ k =  \frac{ - 71}{2}
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