A rectangular field has 80 m length and 48 m breadth.three roads each of 2 m pass through the field such that two roads are parallel to the breadth and the third road parallel to the length.find the area covered by the three roads
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We know that width of each road is 2m.
Length of two of the roads (parallel to the breadth) = breadth = 48m.
Length of one road (parallel to the length) = length = 80m.
i] Area of two roads parallel to the breadth = 2(width * breadth)
= 2( 2*48)
= 2(96)
= 192 m. square
ii] Area of road parallel to the length = width of road * length
= 2 * 80
= 160 m. square
Now, subtract the areas common in both the roads :
We can see that the length and breadth of these common areas is 2 m.
Areas of the common part = (2*2) + (2*2)
= 4 + 4
= 8 m. square
Upon subtracting these from the total area of the roads :
(192 + 160) - 8
344 m. square
The area covered by the three roads is 344 m. square.
Look at the attachment.
Length of two of the roads (parallel to the breadth) = breadth = 48m.
Length of one road (parallel to the length) = length = 80m.
i] Area of two roads parallel to the breadth = 2(width * breadth)
= 2( 2*48)
= 2(96)
= 192 m. square
ii] Area of road parallel to the length = width of road * length
= 2 * 80
= 160 m. square
Now, subtract the areas common in both the roads :
We can see that the length and breadth of these common areas is 2 m.
Areas of the common part = (2*2) + (2*2)
= 4 + 4
= 8 m. square
Upon subtracting these from the total area of the roads :
(192 + 160) - 8
344 m. square
The area covered by the three roads is 344 m. square.
Look at the attachment.
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this is the answer
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