Math, asked by raviverma02486, 1 year ago

A rectangular field has 80 m length and 48 m breadth.three roads each of 2 m pass through the field such that two roads are parallel to the breadth and the third road parallel to the length.find the area covered by the three roads

Answers

Answered by TPS
54
area of road 1(parallel to length) = 2×80=160
area of road 2 (parallel to breadth) = 2×48 = 96
area of road 3 (parallel to breadth) = 2×48 = 96
common areas(a and b)=2×(2×2) = 8m

area covered by road = 160+96+96-8=344 m²

Attachments:

raviverma02486: answer given is 348m^2
TPS: it can't be 348!! it should be 344.....there are 2 intersections...
Answered by gautamisahoo
26
Length of two roads are 48 m each
       Area of these two roads= 2*48*2= 192 m²
Length of one road is 80 m
       Area of this road = 80*2=160 m²
       Common area of these roads= 2*2*2= 8 m²
Area covered by three roads =192 + 160 - 8 = 344 m²
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