a rectangular field has 80 m length and 48 metre breath three roads each of width 2 metre passed through the fields such that two roads are parallel to the breadth and the third parallel to the length find the area covered by the three roads
Answers
Answer:
We know that width of each road is 2m.
Length of two of the roads (parallel to the breadth) = breadth = 48m.
Length of one road (parallel to the length) = length = 80m.
i] Area of two roads parallel to the breadth = 2(width * breadth)
= 2( 2*48)
= 2(96)
= 192 m. square
ii] Area of road parallel to the length = width of road * length
= 2 * 80
= 160 m. square
Now, subtract the areas common in both the roads :
We can see that the length and breadth of these common areas is 2 m.
Areas of the common part = (2*2) + (2*2)
= 4 + 4
= 8 m. square
Upon subtracting these from the total area of the roads :
(192 + 160) - 8
344 m. square
The area covered by the three roads is 344 m. square.
Answer:
344 square metres
Step-by-step explanation:
area of field=80×48=3840sq.m
area of roads=2×48+2×48+2×80-2×2×2
=96+96+160-8
=352-8
=344
area of roads=344sq.m