a rectangular field has 80m ledngth and 48m bredth .Three roads ,each of width 2m pass through the field has such that two roads are parell to the lbreadth abd the thirdd rOadcparellel to the length . Find the area covered by the three roads
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The length of the rectangular field =80m
The breadth of the rectangular field=80m
Two roads having 2m width cross through the field so that the roads become parallel to the length of the field (i.e. 80m).
Therefore,
Area of the two roads=(l×b)
=(80×2)m
=160 sqr. m
as there are two roads, hence it the total area of the two roads will be..(160+160) sqr.m =320 sq.m
Now the third road has crossed the field so that it will be parallel to the breath of the field(i.e. 48m).
hence the area covered by the third road=(l+b)
=(48×2)m
=96 sqr.m
therefore adding the above results of the three road's area, we will get the total area covered bythe three roads which have crossed through the rectangular field =(320+96) sq.m
=416 sqr. m
The breadth of the rectangular field=80m
Two roads having 2m width cross through the field so that the roads become parallel to the length of the field (i.e. 80m).
Therefore,
Area of the two roads=(l×b)
=(80×2)m
=160 sqr. m
as there are two roads, hence it the total area of the two roads will be..(160+160) sqr.m =320 sq.m
Now the third road has crossed the field so that it will be parallel to the breath of the field(i.e. 48m).
hence the area covered by the third road=(l+b)
=(48×2)m
=96 sqr.m
therefore adding the above results of the three road's area, we will get the total area covered bythe three roads which have crossed through the rectangular field =(320+96) sq.m
=416 sqr. m
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