Question

A rectangular field has a diagonal of 50 ft. If the length twice its width, find the area of the lot

Answer 1

let length be 2x.
Breadth be x.
(diagonal of rectangle)^2=l*l+b*b
''''''' =2x*2x+x*x.
'''''''' =4x^2+x^2.
"""""""=5x^2
50=5x^2
50/5 =x^2
10=x^2
X=√10
Area =l*b
=2*√10*√10
Area =20(ft)^2