Question

A rectangular field has an area 2880o sq metre . Its length os twice as long as itś width. What is the length of itś sides.

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

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$\green{\underline \bold{Given :}}$

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• Area of rectangular field = 28800 sq. m

• Length is twice as long as its width

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$\red{\underline \bold{To \: Find:}}$

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• Length of its sides.

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$\large{\orange{\underline{\tt{Solution :-}}}}$

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Let length be 'x'

Let width be 'y'

Hence,

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$\underline{\bold{\texttt{Area of rectangle:}}}$

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$\purple\longrightarrow$ $\sf length \: \times \: breadth$

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$\sf i.e x \: \times \: y = 28800$ -------(1)

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$\purple{\underline \bold{According \: to \: the \ question :}}$

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$\longmapsto \sf 2y = x$ -------(2)

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$\underline{\bold{\texttt{Putting x = 2y in equation (1)}}}$

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$\sf \longmapsto 2y\: \times \: y = 28800$

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$\sf \longmapsto 2y^2 = 28800$

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$\sf \longmapsto y^2 = 14400$

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$\sf \longmapsto y = \sqrt 14400$

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$\sf \longmapsto y = 120m$

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$\underline{\bold{\texttt{Putting y = 120 in equation (2)}}}$

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$\sf \longmapsto 2(120) = x$

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$\sf \longmapsto 240 = x$

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Hence length is 240 m & width is 120 m

$\rule{200}5$

Answer 2

Answer:

length is240 and width is 120

Step-by-step explanation:

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