Question

A rectangular field has length = 160 m and breadth = 120 m. Find :
(i) the perimeter of the field.
(ii) the length of fence required to enclose the field.
(iii) the cost of fencing the field at the rate of 80 per metre.​

Answer 1

$\bigstar\:\:\rm\blue{ANSWER}\:\:\bigstar$

$\bigstar\:\:\rm\red{GIVEN}\:\:\bigstar$

• A Rectangular field has length of 160m and 120m.

$\bigstar\:\:\rm\red{TO\:FIND}\:\:\bigstar$

• The Perimeter of the field

• The length if fence required to enclose the field.

• The cost of fencing at the rate of 80.

$\bigstar\:\:\rm\red{FORMULA\:USED}\:\:\bigstar$

• ${\boxed{\bf{\blue{Perimeter=2(L+B)}}}}}$

Now,

$\implies\rm\blue{2(L+B)}$

$\implies\rm\blue{2(160+120)}$

$\implies\rm\blue{2\cancel{280}}$

$\implies\rm\blue{560m^{2}}$

Hence,The Permeter of the field is 560m².

ii) The length of fence required = Total Perimeter of field.

iii) Cost of fencing the field at per m²=80

Cost of fencing the field of perimeter 560m²=80×560=₹44, 800.

$\huge\bigstar\bigstar\rm{More\:To\:Know}\bigstar\bigstar$

• Perimeter of square = 4× Side

• Area of Square= Side× Side.

• Area of Parallelogram= Base×Height.

Answer 2

${ \underline{ \underline{ \tt{ \huge{ \red{QUESTION }}}}}}$




▪ A rectangular field has length = 160 m and breadth = 120 m



Find:-



( i ) The perimeter of the field


( ii ) The length of fence required to enclose the field


( iii ) The cost of fencing the field at the rate of Rs.80 per metre.



${ \underline{ \underline{ \tt{ \red{ \huge{SOLUTION }}}}}}$



${ \dagger{ \purple{ \bold{ \: \: \: GIVEN }}}}$



${ \underline{ \orange{ \sf{dimension \: of \: rectangular \: field}}}}$



${ \star{ \blue{ \sf{ \: \: \: length = 160m}}}} \\ \\ { \star{ \blue{ \sf{ \: \: \: breadth = 120m}}}}$



${ \dagger{ \bold{ \purple{ \: \: \: TO \: FIND }}}}$



${ \sf{(i) \: \: perimeter \: of \: the \: field}}$



${ \boxed{ \boxed{ \green{ \sf{perimeter = 2(length + breadth)}}}}}$



${ \rightarrow{ \blue{ \sf{perimeter = 2(160 \: m \: + 120 \: m)}}}}$



${ \implies{ \sf{ \blue{perimeter = 2(280 \: m)}}}}$



${ \implies{ \sf{ \blue{ perimeter = 560 \: m}}}}$



${ \sf{(ii) \: length \: of \: fence \: required }}\\ \\ { \sf{ \: to \: enclose \: the \: field}}$



${ \sf{ \blue{ \: = \: perimeter \: of \: the \: field = 560 \: m}}}$



${ \sf{ (iii) \: cost \: of \: fencing \: the \: field}}$



${ \star{ \orange{ \sf { \: \: rate = Rs . \: 80 \: per \: metre}}}}$



${ \blue{ \sf{cost \: of \: fencing}}} \\ \\ { \sf{ \red{ = perimeter \times rate}}}$



${ \rightarrow{ \blue{ \sf{cost \: of \: fencing = 560m \: \times Rs . \frac{80}{m}}}}}$



${ \implies{ \sf{ \blue{cost \: of \: fencing = \: Rs. \: 44800}}}}$