a rectangular field is 112 M long and 100 M wide two Cross Roads each of width 5m are constructed at the centre of this field one is parallel to the length of the field and other is parallel to the breadth of the field find: a area of two Cross Roads
b area of remaining feild
c cost of laying grass in the remaining field at the rate of 2 rupees per metre
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Dear Student ,
Please find below the solution to the asked query :

Length of rectangular field=112 mWidth of rectangular field=100 m.1). Area of cross road=5×112+5×100−5×5=560+500−25=1035 m2 .2). Area of remaining field=Area of rectangular field−Area of cross road=112×100−1035=11200−1035=10165 m2 .3). Assuming cost is & 25 per sq. m . Cost of laying grass in remaining field=25×Area of remaining field=25×10165=& 254125 .If cost is & 25 per sq. cm , then answer is25×101650000=& 2541250000 .
Please find below the solution to the asked query :

Length of rectangular field=112 mWidth of rectangular field=100 m.1). Area of cross road=5×112+5×100−5×5=560+500−25=1035 m2 .2). Area of remaining field=Area of rectangular field−Area of cross road=112×100−1035=11200−1035=10165 m2 .3). Assuming cost is & 25 per sq. m . Cost of laying grass in remaining field=25×Area of remaining field=25×10165=& 254125 .If cost is & 25 per sq. cm , then answer is25×101650000=& 2541250000 .
Vijaytargotra143:
Very good answer
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