Question

a rectangular field is 112 m long and 62 m broad.A cubical tank of edge 6 m is dug at each of the 4 corners of the field and the earth so removed is evenly spread on the remaining field.Find the rise in level.

Answer 1

Total Area of the field = 112 * 62 m^2
                                   = 6944 m^2

Volume of Cubical tank = 6 * 6 * 6
                                       = 216 m^3

Thus
Volume of sand dug out = volume of rectangular field
                            216 = 6944 * H
H = 0.03 m

Answer 2

Answer:

Step-by-step explanation:

area of feild=112*62=6944m^2

area of top of one tank=6^2=36 m^2

so,area of tops of four tanks=36*4=144m^2

area of feild left to spread earth on=6944-144=6800 m^2

volume of one tank=216 m^3

volume of four tanks=216*4=864 m^3