Question

plz help me frnds...

Answer 1

suppose deepu has got 'a' no of marbles
while sudhir got 'b' no of marbles.
 now
a/q            a + b =26


after losing 3 marbles , deepu got = a-3 marbles
                                     sudhir got = b-3 marbles
a/q    (a-3)(b-3) = 91 ⇒ ab - 3(a+b) +9 = 91
                                 ⇒ ab - 3(26) = 82
                                 ⇒ ab = 82 +78 = 160

now forms a quadratic equation, whose roots are a and b

sum of roots = a + b = 26
product of roots = ab = 160

so  eq =          x² - 26x +160 = 0

roots a = 16    and b = 10

hope this helps.

Answer 2

Step-by-step explanation:

Let number of marbles deepak and sudhir has be x and y

after loosing 3 marbles deepak has x-3 marbles and sudhir has y-3 marbles

the product of marbles afyer this situation is 91

(x-3) × (y-3) =91

xy=82+ 3(x+y)

xy=82+ 3×26

xy=160

product of roots=xy

sum of roots =x+y

so the equation

x2-26x+160

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