a rectangular field is 3 2/5 m. long and 2 1/3 m.wide find its perimeter.4 mark solution
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l = 17 / 5 m [ 3 2/5 = 17/5]
b = 7 /3 m. [. 2. 1/3. = 7 / 3]
P. = 2(l+b)
= 2(17/5 + 7/3)
= 2( 51+35 / 15)
= 2 ( 5.73)
= 11.46cm
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