Question

A rectangular field is 30m by 40m. What distance is saved by walking diagonally across the field?



(Answer should be 20, use pythagorus theorem)​

Answer 1

Answer:

Given : ABCD is a rectangular field of Length = 40m, Breadth = 30m, ∠B=90

o

In the right angled triangle ABC,

By Pythagoras Theorem,

AC

2

=AB

2

+BC

2

=30

2

+40

2

=900+1600

=2500

∴AC=

2500

=50m

Distance from A to C through B is

=30+40=70m

Distance saved =70−50=20m.

Answer 2

Answer:

using pythagoras

let b = 30 and p = 40 where as h = h

h2 = b2 + p2

h2 = 30^2+40^2

h2 = 900+1600

h2 = 2500

h = _/2500

h = 50

distance saved = 30 +40 - 50

= 70 - 50 = 20