Math, asked by aaditya230708, 3 months ago

A rectangular field is 50 m by 40 m. It has two roads through its centre, running parallel to Its sides. The width of the longer and the shorter roads are 2 m and 2.5-m-respectively. Find the area of the roads and the area of the remaining portion of the field.​

Answers

Answered by ItzMissAatma
35

Area of the longer road=2×50=100m^2

Area of the smaller Road =

2.5×40= 100 m^2

area of fields=50×40=2000m^2

area common to both the road

=2.5×2=5m^2

area of roads=200-5=195

=1805m^2=ANSWER

Answered by ItsCuteBaby83
4

Step-by-step explanation:

Given:

The width of longer road = 2m

The width of shorter road = 2.5m

The rectangular field is of 50m by 40m

To find:

The “area of Road” and the “remaining portion” of the road

Answer:

The “area of the longer road” = 50×2=100m

The “area of the shorter road” = 40×2.5=100m

“Total area of the rectangular field” = 2×2.5=5m

“Area common” to both the roads =2×2.5=5m

“Total Area of the roads” =100+100−5=195m

“Area of the remaining portion” of the field =2000−195=1805m

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