A rectangular field is 50 m by 40 m. It has two roads through its centre, running parallel to Its sides. The width of the longer and the shorter roads are 2 m and 2.5-m-respectively. Find the area of the roads and the area of the remaining portion of the field.
Answers
Answered by
35
Area of the longer road=2×50=100m^2
Area of the smaller Road =
2.5×40= 100 m^2
area of fields=50×40=2000m^2
area common to both the road
=2.5×2=5m^2
area of roads=200-5=195
=1805m^2=ANSWER
Answered by
4
Step-by-step explanation:
Given:
The width of longer road = 2m
The width of shorter road = 2.5m
The rectangular field is of 50m by 40m
To find:
The “area of Road” and the “remaining portion” of the road
Answer:
The “area of the longer road” = 50×2=100m
The “area of the shorter road” = 40×2.5=100m
“Total area of the rectangular field” = 2×2.5=5m
“Area common” to both the roads =2×2.5=5m
“Total Area of the roads” =100+100−5=195m
“Area of the remaining portion” of the field =2000−195=1805m
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