A rectangular field is 50 m by 40 m. It has two roads through its centre, running parallel to its sides. the width of the longer and the shorter roads are 2m and 2.5 m respectively. find the area of the roads and the area of the remaining portion of the field .(show with diagram)
Answers
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→ Given Question :-
⇒ A rectangular field is 50 m by 40 m. It has two roads through its centre, running parallel to its sides. the width of the longer and the shorter roads are 2m and 2.5 m respectively. find the area of the roads and the area of the remaining portion of the field .(show with diagram).
→ Answer:-
⇒ Let ABCD Be the rectangular field and KLMN and PQRS the two rectangular roads with width 1.8 m and 2.5 m ,respectively.
⇒ Given that length of rectangular field = 50 m
⇒ Breadth of rectangular field = 40 m .
⇒ Area of rectangular field ABCD = 50 m × 40 m
⇒ 2000m²
Area ⇒ of the road KLMN =40 m × 2.5
⇒ 100m²
⇒ Area of the road PQRS = 50 m × 1.8 m
⇒ 90m²
⇒ Clearly area of EFGH is common to the two roads.
⇒ Thus, Area of EFGH = 2.5 m x 1.8 m =
⇒ 4.5 m²
⇒ Hence, Area of the roads =
⇒ Area of KLMN + Area of PQRS – Area of EFGH
⇒ (100 m2 + 90 m2) -4.5 m²
⇒ 185.5m²
⇒ Area of the remaining portion of the field =
⇒ Area of the rectangular field ABCD – Area of the roads
⇒( 2000 – 185.5) m2
⇒ 1814.5m²
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