Math, asked by utkarshchamp532, 4 months ago

A rectangular field is 68 m long and 20 m wide. How many right triangular flower beds, whose sides containing the right angle measure 17 m and 5 m, can be laid in this field?​

Answers

Answered by Aromika
0

Ans of the question is =

Number 0f flower beds = 32

Answered by santoshdutta41
1

Answer:

Answer:

Number of flower beds = 32

Step-by-step explanation:

In the question,

Length of the rectangle, l = 48 m

Width of the rectangle, w = 20 m

Now,

Area of rectangle is given by,

Area = Length x Width

So,

Area = 48 x 20 = 960 m²

Now,

Sides of the right triangle are, 12 m and 5 m.

So,

Area of triangle is given by,

Area=\frac{1}{2}\times base\times heightArea=

2

1

×base×height

So,

Area=\frac{1}{2}\times 12\times 5=30\ m^{2}Area=

2

1

×12×5=30 m

2

Now,

Number of right triangular flower beds which can be laid are,

Number\ of\ triangular\ beds=\frac{Area\ of\ rectangle}{Area\ of\ triangle}Number of triangular beds=

Area of triangle

Area of rectangle

So,

Number\ of\ triangular\ beds=\frac{960\ m^{2}}{30\ m^{2}}=32Number of triangular beds=

30 m

2

960 m

2

=32

Therefore, the number of triangular beds which can be laid in are 32.

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