Question

A rectangular field is 80 m long and 60 m broad.What distance has a man to cover if he walks from one corner of the field to the opposite corner diagonally?

Answer 1

Answer:

100meter

Explanation:

Using Pythagoras theorem:

C

$c ^{2} = a^{2} + b^{2} \\c^{2} = (80)^{2} + (60)^{2} \\ c^{2} = 6400 + 3600 \\c^{2} = (10000)^{2} \\ c = 100$

distance from one corner to opposite corner is 100 meter