Math, asked by ImARandomUser, 6 months ago

A rectangular field is of dimensions 20 m × 15 m. Two paths run parallel to the sides of the rectangle through the centre of the field. The width of the longer path is 2 m and that of the shorter path is 1 m.​

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Answered by 219toshabhatt
3

Answer:

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Step-by-step explanation:

A rectangular field is of dimension 20 m x 15 m. Two paths run parallel to the sides of the rectangle through the centre of the field. The width of the longer path is 2m and that of the shorter path is 1 m. Find  (i) the area of the paths  (ii) the area of the remaining portion of the field  (iii) the cost of constructing the roads at the rate of Rs 10 per sq.

Length of the rectangular field L = 20 m  Breadth B = 15m  Area = L x B  20 x 15 m2  Area of outer rectangle = 300 m2 Area of inner small rectangle =  19 2 192 x  13 2 132  = 61.75 cm2 (i) Area of the path = Area of the outer rectangle – Area of 4 inner small rectangles = (300 – 4(61.75))m2  = (300 – 247) m2  = 53 m2 Area of the paths = 53 m2 (ii) Area of the remaining portion of the field = Area of the outer rectangle – Area of the paths = (300 – 53) m2  = 247 m2 Area of the remaining portion = 247 m2 (iii) Cost of constructing 1 m2 road = Rs 10 ∴ Cost of constructing 53 m2 road = Rs 10 x 53  = Rs 530 ∴ Cost of constructing road = Rs 530

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