A rectangular field of dimensions 160 m x 80 m has four paths through it, two
paths of 2 m parallel to the breadth and two paths each of 3 m width parallel to t
length.
(i) Find the area of the paths.
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Rectangular field 160 * 80 m having 4 paths 2 of 2m Parallel to length & 2 of 3m parallel to breadth then Area of Paths = 1256 m²
Step-by-step explanation:
A rectangular field of dimensions 160 m x 80 m
Length = 160 m
Breadth = 80 m
two paths of 2 m parallel to the breadth
=> Internal length = 160 - 2 - 2 = 156 m
two paths each of 3 m width parallel to length
=> internal breadth = 80 - 3 - 3 = 74 m
Area of Path = 160 * 80 - 156 * 74
= 1256 m²
Another Way to solve :
two paths of 2 m parallel to the breadth
Area = 2 * 2 * 80 = 320 m²
two paths each of 3 m width parallel to length
Area = 2 * 3 * 160 = 960 m²
These paths will intersect at 4 points
Area of intersection =4 * 2 * 3 = 24 m²
Area of Path = 320 + 960 - 24 = 1256 m²
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