A rectangular field which is twice long as it's width,has an area of 14450 Sq.m.find the perimeter.
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Answered by
1
Answer:
Area = length x width
A = L x W
14450 = (2w) x w <--- length is twice the width
14450 = 2w^2
7225 = w^2
w = 85
Length is Area/Width = 14450/85 = 170
Perimeter = 2 * length + 2 * width
= 2 * 170 + 2* 85
= 510
Answered by
2
Answer:
Let the length be 2x
abd breadth be x
A/q,
(2x)×(x) =14450
2x^2=14450
x^2 =7225
x=85
Hence , length=2×85
=170m.
and breadth = 85m
perimeter=2(l+b)
=2(85+170)=2×255
=510m
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