Math, asked by muhammadaltaf7002, 10 months ago

A rectangular field which is twice long as it's width,has an area of 14450 Sq.m.find the perimeter. ​

Answers

Answered by nafizandakildeathlyr
1

Answer:

Area = length x width

A = L x W

14450 = (2w) x w <--- length is twice the width

14450 = 2w^2

7225 = w^2

w = 85

Length is Area/Width = 14450/85 = 170

Perimeter = 2 * length + 2 * width

= 2 * 170 + 2* 85

= 510

Answered by prernaramanramantn
2

Answer:

Let the length be 2x

abd breadth be x

A/q,

(2x)×(x) =14450

2x^2=14450

x^2 =7225

x=85

Hence , length=2×85

=170m.

and breadth = 85m

perimeter=2(l+b)

=2(85+170)=2×255

=510m

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