A rectangular garden 10m by 16m is to be surrounded by a concrete walk of uniform width. Given that area of the walk is 120 square metres, assuming the width of the walk to be x,dorm an equation in x and solve it to find the value of x
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Answered by
10
(10+2x)(16+2x)-160 = 120
x^2+13x-30 = 0
x= 2 m
x^2+13x-30 = 0
x= 2 m
Answered by
1
Consider ABCD as a rectangular garden
Length = 10 m
Breadth = 16 m
So the area of ABCD = l × b
Substituting the values
= 10 × 16
= 160 m2
Consider x m as the width of the walk
Length of rectangular garden PQRS = 10 – x – x = (10 – 2x) m
Breadth of rectangular garden PQRS = 16 – x – x = (16 – 2x) m
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