Math, asked by amandecoration9156, 10 months ago

A rectangular Garden 78 metre long and 35 metre broad has a uniform path 1 metre wide all around it on the outside find the area of the path

Answers

Answered by VANTE
16

Area of ABCD =35m *78m

=2730m²

JM=35m+1+1

=37m

JK=78+1+1

=80m

Area of JKLM = length x breadth

= 37 X 80

=2960m²

area of path = area of JKLM -area of ABCD

=2960 - 2730

=230 m²

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Answered by ƦαíηвσωStαƦ
13

\huge\bf{\underline{\purple{Solution:-}}}

Let PQRS be the rectangular garden and ABCD be the external boundary of the path.

\bf\underline{\red{\:\:\:\:\:\:\:\:We\: have:-\:\:\:\:\:\:\:}}

  • Length PQ = 78 m
  • Breadth QR = 35 m

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

\bullet\;\;\underline{\textbf{\textsf{Area of rectangle PQRS = PQ × QR}}}

\sf {\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: = 78\:m \times 35\:m} \\

\sf {\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: = 2730\:m^2} \\

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\bullet\;\;\underline{\textbf{\textsf{Length AB = 78 m + 1m + 1m}}}

\sf {\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 80\:m} \\

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\bullet\;\;\underline{\textbf{\textsf{Breadth BC = 35 m + 1m + 1m}}}

\sf {\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 37\:m} \\

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\bullet\;\;\underline{\textbf{\textsf{Area of rectangle ABCD = AB × BC}}}

\sf {\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: = 80\:m \times 37\:m} \\

\sf {\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: = 2960\:m^2} \\

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\bullet\;\;\underline{\textbf{\textsf{Area of path = Area of rectangle ABCD - Area of rectangle PQRS}}}

\sf {\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 2960\:m^2 - 2730\:m^2} \\

\sf {\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 230\:m^2} \\

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\sf\underline{\purple{\:\:\: \therefore Area\:of\:path = 230\:m^2\:\:\:}}

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