Question

A rectangular garden has a width that is 8 feet less than twice the length. Find the dimensions if the perimeter is 20 feet. Using Polya's fourth principle

Answer 1

Answer:

Let L be the length of the rectangle and W be its width.

(1) W = 2L - 8

Perimeter is 2(W + L) = 20

W + L = 10

Substituting (1) into this equation:

(2L - 8) + L = 10

3L = 18

L = 6 ft

W = 2L - 8 = 4 ft