A rectangular garden in our school has an area of 84 m^2 and a perimeter of 38 m. If the length is 8 m greater than the width, find its length and its width.
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Answer:
hey here is ur answer
Step-by-step explanation:
38/2=19, half of the perimeter
84=2*2*3*7=(2*2*3)*7=12*7
the length and width are 12m and 7m
if you want quadratic equations...
P=2l+2w
38=2l+2w
19=l+w
l=19-w
A=lw
84=(19-w)w
84=-w^2+19w
w^2-19w+84=0
factor
84=2*2*3*7=12*7
(w-12)(w-7)=0
w-12=0
w=12
w-7=0
w=7
just like what we got before
hope it will help you
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