Question

A rectangular garden is 120m long and 90m broad. four paths pass through the garden such that two paths each width 2.2m are parallel to the breadth and two paths each of width 1.8m are Parnell to the length find the area of the path

Answer 1

The area of the path is 812.16 $m^2$

Solution:

Given, a rectangular garden is 120m long and 90m broad.  

Four paths pass through the garden such that two paths each width 2.2m are parallel to the breadth  

Then, length of each path is 90m [That is width of garden and path is parallel to breadth]

$\text { Area of each path }=90 \times 2.2=9 \times 22=198 \mathrm{m}^{2}$

And two paths each of width 1.8m are parallel to the length  

Then, length of each path is 120 m [that is length of garden and path is parallel to length.

Area of each path = 120 x 1.8 = 12 x 18 = 216 $m^2$

Now, there are 4 crossing over 4 paths.

Dimensions of each crossing is 2.2m x 1.8m.

Then, area of each crossing = 2.2 x 1.8 = 3.96  $m^2$

Now,  

Total area of path= 2 x area of path parallel to length + 2 x area of path parallel to width – 4 x area of crossing.

Area of path = 2 x 216 + 2 x 198 – 4 x 3.96

= 432 + 396 – 15.84 = 812.16  

Hence, the area of the path is 812.16  $m^2$