Math, asked by JasraflKritafarooq, 1 year ago

A rectangular garden is 150 m long and 140 m wide. It has two roads, each 1 metre 50 cm wide running within it, one parallel to the breadth. Find the area of the roads and the cost of repairing the roads at Rs.1.20 per square metre.

Answers

Answered by Golda
24
Solution:-
There is a mistake in the question. I think that the one road is parallel to the breadth then the other must be parallel to the length.
Length of the road 1 = 150 m and Breadth of the road 1 = 1.5 m
Area of the road 1 parallel to the length = 150*1.5 
= 225 sq m
Length of the road 2 = 140 m and Breadth of the road 2 = 1.5 m
Area of the road 2 parallel to the breadth = 140*1.5
= 210 sq m
Since both the roads have a square of side 1.5 m in common where these two roads intersect each other.
So, the area of this common square portion = 1.5*1.5
= 2.25 sq m
Area of the two roads that has to be repaired = (225 + 210) - 2.25
= 435 - 2.25 
= 432.75 sq m
Cost of repairing the roads = 432.75 × 1.2
Total cost of repairing the roads = Rs. 519.30
Answer.
Answered by priyagupta1153
1

I hope this answer is right

Attachments:
Similar questions