A rectangular garden is 150 m long and 140 m wide. It has two roads, each 1 metre 50 cm wide running within it, one parallel to the breadth. Find the area of the roads and the cost of repairing the roads at Rs.1.20 per square metre.
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Solution:-
There is a mistake in the question. I think that the one road is parallel to the breadth then the other must be parallel to the length.
Length of the road 1 = 150 m and Breadth of the road 1 = 1.5 m
Area of the road 1 parallel to the length = 150*1.5
= 225 sq m
Length of the road 2 = 140 m and Breadth of the road 2 = 1.5 m
Area of the road 2 parallel to the breadth = 140*1.5
= 210 sq m
Since both the roads have a square of side 1.5 m in common where these two roads intersect each other.
So, the area of this common square portion = 1.5*1.5
= 2.25 sq m
Area of the two roads that has to be repaired = (225 + 210) - 2.25
= 435 - 2.25
= 432.75 sq m
Cost of repairing the roads = 432.75 × 1.2
Total cost of repairing the roads = Rs. 519.30
Answer.
There is a mistake in the question. I think that the one road is parallel to the breadth then the other must be parallel to the length.
Length of the road 1 = 150 m and Breadth of the road 1 = 1.5 m
Area of the road 1 parallel to the length = 150*1.5
= 225 sq m
Length of the road 2 = 140 m and Breadth of the road 2 = 1.5 m
Area of the road 2 parallel to the breadth = 140*1.5
= 210 sq m
Since both the roads have a square of side 1.5 m in common where these two roads intersect each other.
So, the area of this common square portion = 1.5*1.5
= 2.25 sq m
Area of the two roads that has to be repaired = (225 + 210) - 2.25
= 435 - 2.25
= 432.75 sq m
Cost of repairing the roads = 432.75 × 1.2
Total cost of repairing the roads = Rs. 519.30
Answer.
Answered by
1
I hope this answer is right
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