A rectangular glass tank is half filled with water. The measurements of the tank are height of 30 cm, breadth of 25 cm and 20 cm .by how much in terms of centimetres , will the water level rise if a solid cylindrical piece of iron with a diameter of 6 cm and length of 10 cm , is dropped into the water ?
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Solution :-
The water level rise in centimeters = Volume of cylinder/Area of the floor of water tank
Volume of cylindrical piece of iron = πr²h
Diameter of cylindrical piece of iron = 6 cm
Radius = 6/2 = 3 cm
Height = 10 cm
⇒ 22/7*3*3*10
⇒ 1980/7
= 282.857 cu cm
Area of the floor of water tank = Length*Breadth
⇒ 20*25
= 500 sq cm
Rise in the water level = Volume of cylindrical piece of iron/Area of the floor of water tank
⇒ 282.857/500
⇒ 0.5657 cm or 0.57 cm (Approximately)
So, rise in the water level will be 0.57 cm
Answer.
The water level rise in centimeters = Volume of cylinder/Area of the floor of water tank
Volume of cylindrical piece of iron = πr²h
Diameter of cylindrical piece of iron = 6 cm
Radius = 6/2 = 3 cm
Height = 10 cm
⇒ 22/7*3*3*10
⇒ 1980/7
= 282.857 cu cm
Area of the floor of water tank = Length*Breadth
⇒ 20*25
= 500 sq cm
Rise in the water level = Volume of cylindrical piece of iron/Area of the floor of water tank
⇒ 282.857/500
⇒ 0.5657 cm or 0.57 cm (Approximately)
So, rise in the water level will be 0.57 cm
Answer.
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