Question

A rectangular grassy plot is 125m long,and 74m broad.It has a path 2.5m wide all around it on the inside. Find the cost of levelling the path at rupees 6.80m^2.

Answer 1

125×2.5 + 74× 2.5 _2.5 × 2.5
= 491.25
=Cost = 6.80 ^2
=46.24
= 491.25 × 46.24
= 22715.4

Hope it helps you
If not sorry

Answer 2

✬ Cost = Rs 6596 ✬

Step-by-step explanation:

Given:

• Length and Breadth of rectangular grassy plot is 125 m and 74 m respectively.
• Width of Park which is inside the grassy path is 2.5 m
• Cost of levelling the path is Rs 6.80/m²

To Find:

• What is cost of leveling the path?

Solution: Let ABCD be a rectangular grassy path and EFGH is a rectangle inside this.

★ Area of Rectangle = ( Length x Breadth ) ★

• In rectangular grassy path ABCD •

• Length = AB = 125 m
• Breadth = BC = 74 m

$\small\implies{\sf }$ Area of ABCD = AB x BC

$\small\implies{\sf }$ Area of ABCD = (125 x 74) m²

$\small\implies{\sf }$ Area of ABCD = 9250 m²

• In rectangle EFGH •

• Length = EF = ( AB – 2.5 + 2.5 ) = ( 125 – 5 )=120 m

• Breadth = FG = ( BC – 2.5 + 2.5 ) = ( 74 – 5 ) = 69 m

$\small\implies{\sf }$ Area of EFGH = EF x FG

$\small\implies{\sf }$ Area of EFGH = (120 x 69) m²

$\small\implies{\sf }$ Area of EFGH = 8280 m²

Now, We have to find the area of path which is between ABCD and EFGH, so to find that area we have to subtract the Area of EFGH from the ABCD.

$\small\implies{\sf }$ Area of Path = Ar ( ABCD – EFGH )

$\small\implies{\sf }$ Area of path = (9250 – 8280) m²

$\small\implies{\sf }$ Area of path = 970 m²

Hence, The area of path is 970 m²

→ Cost of leveling 1 m² = Rs 6.80

∴ Cost of leveling 970 m² = Rs (6.80 x 970) = Rs 6596

Hence, The cost of levelling the path is Rs 6596.