A rectangular hall has semicircular walls on its two sides , as shown If the dimensions of the rectangular portion are 12 metres and 7 metres . Calculate the area covered by the hall.
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area covered by the hall is 122.5 m²
see figure ,
length of rectangle , l = 12m
breadth of rectangle, b = 7m
radius of semicircle, r = 7/2 m = 3.5 m
area covered by the hall = 2 × area of semicircular + area of rectangle
= 2 × πr²/2 + l × b
= πr² + l × b
= 22/7 × (3.5)² + 12 × 7
= 22 × 0.5 × 3.5 + 84
= 11 × 3.5 + 84
= 38.5 + 84
= 122.5 m²
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Answer:
122.5 m
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