Question

the sum of three consecutive even numbers is 138

Answer 1

Let numbers are ( 2x ) , 2( x + 1 ) , 2( x + 2 )

Their sum = 138

=> 2x + 2( x + 1 ) + 2( x + 2 )= 138

=> x + x + 1 + x + 2 = 69

=> 3( x + 1 ) = 69

=> x + 1 = 23

=> x = 22

Required numbers are

2x = 2(22) = 44

2( x + 1 ) = 2( 23 ) = 46

2( x + 2 ) = 2(24) = 48

Answer 2

Here is your solution

Let,
The first even integer be:x

Then the second even integer is:-
x+2

Then the third even integer is:-
x+2+2=x+4

Sum of three consecutive even numbers =138

A/q

(x)+(x+2)+(x+4)=138
3x+6=138
3x=138-6
3x=132
x=44
now

The first integer is: x=44

the second integer is: x+2=44+2 = 46

the third integer is: x+4=44+4=48

Hope it helps you