Question

a rectangular hall is 12 m long and 6 m broad its flooring is to be made of square tiles of side 30 cm how many times will fit in the whole how many World be required if types of side 15 centimetre where use
$\gamma = 12 m = 12000 cm b = 6m = 600cm$

Answer 1

l=12m=12×100cm=1200cm. (1m=100cm)
b=6m=6×100cm=600cm
area of room=l×b
1200×600=720000cm²
a=30cm
area of square tile=a×a
30×30=900cm²
tiles required=area of room/area of tiles
720000/900=800tiles required ans
in case of 15 cm tiles
a=15cm
area of tile=15×15=225cm²
required tiles=area of room/area of tile
720000/225=3200tiles required
this is the required answer

Answer 2

Step-by-step explanation:

Area of the rectangular hall = length × breadth = 12 × 6 = 72 sq.m.

Side of the square shaped tile = 30 cm = 30/100 m …[1cm = 1/100 m] = 3/10 m Area of the tile = (side)2 = (3/10)2 = 9/100 sq.m Number of tiles required = (Area of the hall)/(Area of each tile) = 75 ÷ 9/100 = 72 x 100/9 = 800 ∴ 800 square shaped tiles of 30 cm side will be required. If the side of the square is reduced to half, its area will become 1/4 times the original. i. e. number of tiles required will become 4 times the original tiles. ∴ Number of tiles required = 4 × number of tiles of side 30 cm = 4 × 800 = 3200 ∴ 3200 square shaped tiles of 15 cm side will be required.